cadence_mix
Answered against 22 years of US equities and 12 years of US options data and published with the query that produced it. This result is stored as of 2026-09-25, from us-dividend-frequency-for-russian-investors.
| bucket | company_count | share_pct |
|---|---|---|
| 4 выплаты | 785 | 63 |
| 12 и более выплат | 124 | 9.9 |
| 1 выплата | 110 | 8.8 |
| 2 выплаты | 96 | 7.7 |
| 3 выплаты | 89 | 7.1 |
| иное число выплат | 43 | 3.4 |
- Rows × columns
- 6 × 3
- Computed
- Completeness
- No missing values
- Source
- US exchange, SIP and OPRA market data
- Licence
- Strasmore terms · free, no signup
What each column holds
| Column | Type | Range | Notes |
|---|---|---|---|
bucket |
text | 6 distinct values (1 выплата, 12 и более выплат, 2 выплаты…) | |
company_count |
number | 43 to 785 | count |
share_pct |
number | 3.4 to 63 | percent |
Computed from Strasmore's warehouse of US exchange, SIP and OPRA market data. Equity prices are delayed; options greeks and implied volatility are end-of-day. This result is stored, not recomputed on load — it is exactly the numbers that were returned on , and the query below is what returned them.
Run it yourself
This is the exact query behind the result above. Change a ticker, a date or a column and run it against the warehouse — no account, no key. The no-signup tier is smaller than the one this page was computed on; a query that reaches past it comes back saying which plan runs it.
WITH liquid AS
(
SELECT ticker
FROM global_markets.stocks_daily_aggs
WHERE date >= today() - 120
AND ticker NOT IN ('SPCX')
GROUP BY ticker
HAVING avg(volume) >= 1000000
AND avg(close) >= 5
),
payers AS
(
SELECT
d.ticker AS ticker,
countDistinct(d.ex_dividend_date) AS payouts
FROM global_markets.stocks_dividends AS d
INNER JOIN liquid AS l ON l.ticker = d.ticker
WHERE d.ex_dividend_date >= today() - 365
AND d.ex_dividend_date < today()
AND d.cash_amount > 0
GROUP BY d.ticker
)
SELECT
multiIf(p.payouts >= 12, '12 и более выплат',
p.payouts = 4, '4 выплаты',
p.payouts = 2, '2 выплаты',
p.payouts = 1, '1 выплата',
p.payouts = 3, '3 выплаты',
'иное число выплат') AS bucket,
count() AS company_count,
round(100.0 * count() / any(t.total), 1) AS share_pct
FROM payers AS p
CROSS JOIN (SELECT count() AS total FROM payers) AS t
GROUP BY bucket
ORDER BY company_count DESC
Работайте с этими данными в своём ИИ-ассистенте
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